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---
lastmod: "2022-01-01T22:20:19.0000000+00:00"
author: patrick
categories:
- creative
- mathematical_summary
comments: true
date: "2013-08-31T00:00:00Z"
math: true
aliases:
- /wordpress/archives/379/index.html
- /creative/mathematical_summary/slightly-silly-sylow-pseudo-sonnets/index.html
- /slightly-silly-sylow-pseudo-sonnets/index.html
title: Slightly silly Sylow pseudo-sonnets
---
This is a collection of poems which together prove the [Sylow theorems][1].
# Notes on pronunciation
* Pronounce \\( \vert P \vert \\) as "mod P", \\(a/b\\) or \\(\dfrac{a}{b}\\) as "a on b", and \\(=\\) as "equals".
* \\(a^b\\) for positive integer \\(b\\) is pronounced "a to the b".
* \\(g^{-1}\\) is pronounced "gee inverse".
* "Sylow" is pronounced "see-lov", for the purposes of these poems.
* \\(p\\) and \\(P\\) and \\(n_p\\) are different entities, so they're allowed to rhyme.
# [Monorhymic][4] Motivation [^notsonnet]
Suppose we have a finite group called \\(G\\).
This group has size \\(m\\) times a power of \\(p\\).
We choose \\(m\\) to have coprimality:
the power of \\(p\\)'s the biggest we can see.
Then One: a subgroup of that size do we
assert exists. And Two: such subgroups be
all conjugate. And \\(m\\)'s nought mod \\(n_p\\),
while \\(n_p = 1 \pmod{p}\\); that's Three.
# Theorem One
## Little [Lemmarick][5]
*Subtitle: "The size of the normaliser \\(N\\) of a maximal \\(p\\)-subgroup \\(P\\) has \\(N/P\\) coprime to \\(p\\)"*
There was a \\(p\\)-subgroup of \\(G\\)
(by Cauchy). The largest was \\(P\\).
Let \\(N\\) normalise,
Take \\(\dfrac{N}{P}\\)'s size,
Suppose that it's zero mod \\(p\\).
---
Now \\(\dfrac{N}{P}\\) also has some
p-subgroup (by Cauchy); take one.
Take it un-projected,
\\(P\\)'s most big? Corrected!
We've found one sized \\(p \vert P \vert \\): done.
## Introductory Interlude (to the tune of "[Jerusalem](https://en.wikipedia.org/wiki/Jerusalem_%28hymn%29)")
*Subtitle: "\\(\{P\}\\) is an orbit of size \\(1\\) under the conjugation action of \\(P\\) on the set of \\(G\\)-conjugates of \\(P\\)"*
Let \\(X\\) be \\(P\\)'s orbit under \\(G\\)
Acting by conjuga-ti-on.
Mod \\(G\\) o'er \\(N\\)'s the size of \\(X\\)
The Orbit/Stabiliser's done.
And in its turn, \\(P\\) acts on \\(X\\)
By conjugating, as before,
Then \\(P\\) is certainly all alone:
Its orbit is itself, no more.
---
Let \\(gPg^{-1}\\) be alone,
\\(P\\) stabilises it, and hence
\\(pgPg^{-1}p^{-1}\\)
Is \\(gPg^{-1}\\) - from whence
We conjugate by \\(g^{-1}\\):
\\(g^{-1}Pg\\) fixes \\(P\\).
\\(g^{-1}Pg\\) is in \\(N\\),
so \\(\pi\\) applies. From this, we'll see:
## [Cinquain][6] Claim [^cinquain]
*Subtitle: "\\(\{P\}\\) is the only orbit of size \\(1\\)"*
A claim:
\\(\pi(g^{-1}Pg)\\) is \\({1}\\).
Call it \\(K\\). If false, \\(p\\)
divides \\( \vert K \vert \\),
as \\(\pi\\)
a hom [^hom].
Also, \\( \vert K \vert \\)
divides \\( \vert N/P \vert \\)
(Lagrange). Then Lemmarick proves: \\(K\\)
Is \\({1}\\).
## [Trochaic Tetrameter][7] Tying Together [^rhyme]
*Subtitle: "\\(\{P\}\\) is Sylow, since \\(G/N\\) has size coprime to \\(p\\)"*
\\(\pi\\) has kernel \\(P\\) - but also
\\(K\\) is \\({1}\\), so lies inside it.
\\(P\\) contains \\(g^{-1}Pg\\);
Both have size \\(p^a\\). So
since they're finite, they're the same set.
Any set alone in orbit
must be \\(P\\). The class equation
Tells us \\( \vert G \vert / \vert N \vert \\) is
Just precisely \\(1 \pmod{p}\\). Then
\\( \vert G \vert / \vert P \vert \\) is not a
multiple of \\(p\\) because it's
\\( \vert \dfrac{N}{P} \vert \\) multiplied by
\\(\dfrac{ \vert G \vert }{ \vert N \vert }\\) and \\(p\\) can't
possibly divide those two. So
Maximal the power of \\(p\\) is:
\\(P\\)'s a Sylow \\(p\\)-subgroup.
# Theorem Two - Quad-[quatrain][8] [^quatrain]
A Sylow \\(p\\)-subgroup let \\(Q\\) be:
a subgroup, size \\(p^a\\).
Because it's the same size as was \\(P\\),
it acts on \\(X\\) in the same way.
---
Mod \\(p\\), we have \\( \vert X \vert \\) is \\(1\\) -
the orbits of \\(Q\\) will divide it;
Now invoke the class equation:
an orbit, size \\(1\\), lies inside it.
---
We dub this one \\(gPg^{-1}\\),
then \\(g^{-1}Qg\\)'s in \\(N\\).
Projection works just as well in verse:
\\(\pi(g^{-1}Qg)\\) is \\({1}\\).
---
The previous poem's our saviour:
\\(g^{-1}Qg\\) is in \\(P\\).
The Pigeonhole tells its behaviour:
that \\(P\\) is \\(g^{-1}Qg\\).
# Theorem Three - Hindmost [Haiku][9] [^haiku]
\\( \vert X \vert \\): \\(1 \pmod{p}\\)
Orbit \\(X\\) divides \\(G\\)'s size:
We have proved the Third.
[^notsonnet]: This is not a sonnet - it is six lines too short, and is monorhymic rather than following a more varied rhyme scheme. I started out intending it to be a sonnet, but all the rhymes for "p", "G" and so forth were irresistible. "Power" is a monosyllable.
[^cinquain]: I use a form of reverse cinquain, with syllable count 2,8,6,4,2,2,4,6,8,2.
[^hom]: "Hom", of course, is short for "homomorphism". Imre Leader used it all the time, so I took it to be legitimate.
[^rhyme]: This section is unrhymed; although Shakespeare rhymes his tetrameter, Longfellow doesn't. The strong iambic nature of English makes enjambement very natural to write when you're constrained to trochees, so I have just gone with the flow.
[^quatrain]: Quatrains have a variety of allowable rhyme schemes, but I plumped for ABAB for the sake of variety. Yes, "N" rhymes with "one". For the purposes of scansion, pronounce each line as the first line of a limerick, with an optional weak syllable at the end if necessary.
[^haiku]: I know that a haiku should mention a season, etc - but that is a constraint I am willing to relax. Gareth pointed out that if "sum" and "size" were synonymous, then " \|X\| : 1 (mod p)/Orbit X divides G's sum/A proof of the Third" would mention the season "sum-A".
[1]: {{< ref "2013-06-26-sylow-theorems" >}}
[2]: http://tartarus.org/gareth/
[3]: http://mmeblair.tumblr.com/post/61532912275/carnival-of-mathematics-102-my-summation-of-other
[4]: https://en.wikipedia.org/wiki/Monorhyme
[5]: https://en.wikipedia.org/wiki/Limerick_%28poetry%29
[6]: https://en.wikipedia.org/wiki/Cinquain
[7]: https://en.wikipedia.org/wiki/Trochaic_tetrameter
[8]: https://en.wikipedia.org/wiki/Quatrain
[9]: https://en.wikipedia.org/wiki/Haiku